Odpowiedź:
[tex]3^{x+6}>27\\\\3^{x+6}>3^3\\\\x+6>3\\\\x>3-6\\\\x>-3\\\\x\in(-3,+\infty)[/tex]
[tex]6^{5-x}\leq 6^{5x-1}\\\\5-x\leq 5x-1\\\\-x-5x\leq -1-5\\\\-6x\leq -6\ \ /:(-6)\\\\x\geq 1\\\\x\in\langle1,+\infty)[/tex]
[tex](0,1)^{8x-3}>(0,1)^{2x-2}\\\\8x-3<2x-2\\\\8x-2x<-2+3\\\\6x<1\ \ /:6\\\\x<\frac{1}{6}\\\\x\in(-\infty,\frac{1}{6})[/tex]
