Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]h = 6\sqrt{2}\\oraz\\h = \frac{a\sqrt{3}}{2}\\\\\frac{a\sqrt{3}}{2} = 6\sqrt{2} \ \ \ |\cdot2\\\\a\sqrt{3} = 12\sqrt{2} \ \ \ /:\sqrt{3}\\\\a = \frac{12\sqrt{2}}{\sqrt{3}} = \frac{12\sqrt{2}}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = \frac{12\sqrt{2\cdot3}}{3}=\underline{ 4\sqrt{6}}[/tex]
[tex]P = \frac{a^{2}\sqrt{3}}{4}\\\\P = \frac{(4\sqrt{6})^{2}\cdot\sqrt{3}}{4} = \frac{16\cdot6\cdot\sqrt{3}}{4}=4\cdot6\sqrt{3}\\\\\boxed{P =24\sqrt{3}} \ \ [j^{2}][/tex]
