Odpowiedź :
Pole podstaw
[tex] \not2 \times \frac{8 \times 6}{ \not2} = 48 {cm}^{2} [/tex]
Krawędź podstawy
[tex] {4}^{2} + {3}^{2} = {x}^{2} \\ 16 + 9 = {x}^{2} \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5cm[/tex]
Pole ścian bocznych
[tex]4 \times 5 \times 4 = 20 \times 4 = 80 {cm}^{2} [/tex]
[tex]Pc = 48 {cm}^{2} + 80 {cm}^{2} = \underline{ 128 {cm}^{2} }[/tex]