Odpowiedź :
[tex]1)\\\\-9(2-x)^2-(1-3x)(3x+1) < 11\\\\-9(4-4x+x^2)-(1-9x^2) < 11\\\\-36+36x-9x^2 - 1+9x^2 < 11\\\\36x < 11+36+1\\\\36x < 48\ \ |:36\\\\x < \frac{48}{36}\\\\x < \frac{4}{3}\\\\x < 1\frac{1}{3}[/tex]
[tex]2)\\\\ ( \frac{1}{4}x+2)^2+ \frac{1}{4}(1- \frac{1}{2} x)(1+ \frac{1}{2}x) > 0\\\\\frac{1 }{16}x^2+x+4+\frac{1}{4}(1-\frac{1}{4}x^2) > 0\\\\\frac{1 }{16}x^2+x+4+\frac{1}{4} -\frac{1}{16}x^2 > 0 \\\\x > -4\frac{1}{4}[/tex]

