Odpowiedź :
a)
[tex]7-A = 4B\\\\-A = 4B-7 \ \ |:(-1)\\\\\boxed{A = 7-4B}[/tex]
b)
[tex]Ab = 2d \ \ |:b\\\\\boxed{A = \frac{2d}{b}}[/tex]
c)
[tex]\frac{A}{m+n} = 2 \ \ |\cdot(m+n)\\\\\boxed{A = 2(m+n)}[/tex]
a)
[tex]7-A = 4B\\\\-A = 4B-7 \ \ |:(-1)\\\\\boxed{A = 7-4B}[/tex]
b)
[tex]Ab = 2d \ \ |:b\\\\\boxed{A = \frac{2d}{b}}[/tex]
c)
[tex]\frac{A}{m+n} = 2 \ \ |\cdot(m+n)\\\\\boxed{A = 2(m+n)}[/tex]