Pole podstawy
[tex]6 \times \frac{ {a}^{2} \sqrt{3} }{4} =6 \times \frac{ {9}^{2} \sqrt{3} }{4} = 6 \times \frac{81 \sqrt{3} }{4} = 6 \times 20.25 \sqrt{3} = 121.5 \sqrt{3} [/tex]
Objętość
[tex] \frac{121.5 \sqrt{3} \times 4 }{3} = \frac{486 \sqrt{3} }{3} = 162 \sqrt{3} [/tex]
