Pole podstawy
[tex] \frac{ {a}^{2} \sqrt{3} }{4} = \frac{ {4}^{2} \sqrt{3} }{4} = \frac{16 \sqrt{3} }{4} = 4 \sqrt{3} [/tex]
Objętość
[tex]4 \sqrt{3} \times 3 = 12 \sqrt{3} [/tex]
