[tex]Dane:\\V = 0,5 \ m^{3}\\F_{wyp} = 510 \ N\\g = 10\frac{N}{kg}}\\Szukane:\\d = ?\\\\Rozwiazanie\\\\F_{wyp} = d\cdot g\cdot V \ \ /:(g\cdot V)\\\\d = \frac{F_{wyp}}{g\cdot V}\\\\d = \frac{510 \ N}{10\frac{N}{kg}\cdot0,5 \ m^{3}}\\\\\boxed{d = 102\frac{kg}{m^{3}}}[/tex]
