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porównaj ułamki
5/6 i 7/12
1/4 i 3/8
5/6 i 3/4
2/3 i 3/5
3/4 i 2/3
5/8 i 4/6​


Odpowiedź :

1) [tex] \frac{5( \times 2)}{6( \times 2)} \: \: i \: \: \frac{7}{12} = \frac{10}{12} \: \: > \: \: \frac{7}{12} [/tex]

2) [tex] \frac{1( \times 2)}{4( \times 2)} \: \: i \: \: \frac{3}{8} = \frac{2}{8} < \frac{3}{8} [/tex]

3) [tex] \frac{5( \times 2)}{6( \times 2)} \: \: i \: \: \frac{3( \times 3)}{4( \times 3)} = \frac{10}{12} > \frac{9}{12} [/tex]

A TERAZ STOP! SPRÓBUJ ROZWIĄZAĆ RESZTĘ SAM*

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Już? To możesz sobie sprawdzić ❤️❤️:

4) [tex] \frac{2( \times 5)}{3( \times 5)} \: \: i \: \: \frac{3( \times 3)}{5( \times 3)} = \frac{10}{15} > \frac{9}{15} [/tex]

5) [tex] \frac{3( \times 3)}{4( \times 3)} \: \: i \: \: \frac{2( \times 4)}{3( \times 4)} = \frac{9}{12} > \frac{8}{12} [/tex]

6) [tex] \frac{5( \times 3)}{8( \times 3)} \: \: i \: \: \frac{4( \times 4)}{6( \times 4)} = \frac{15}{24} < \frac{16}{24} [/tex]

Mogłabym prosić o naj? Z góry dzkk❤️