Obliczenia
[tex]-0,3^2=-(0,3\cdot0,3)=-0,09\\\\(-\frac{7}{10})^0=1 \ (\text{zawsze a}^0=1, \ \text{gdy a}\neq0)\\\\(1\frac{4}{7})^2=(\frac{11}{7})^2=\frac{11}{7}\cdot\frac{11}{7}=\frac{121}{49}=2\frac{23}{49}\\\\(-1\frac{1}{4})^3=(-\frac{5}{4})^3=-\frac{5}{4}\cdot(-\frac{5}{4})\cdot(-\frac{5}{4})=-\frac{125}{64}=-1\frac{61}{64}[/tex]
