Odpowiedź :
[tex]\frac{2^{8}-2^{7}}{16^{2}} =\frac{2^{7}\cdot2-2^{7}}{16^{2}}= \frac{2^{7}(2-1)}{(2^{4})^{2}} = \frac{2^{7}\cdot1}{2^{8}} =\frac{2^{7}}{2^{8}} = 2^{7-8} = 2^{-1} = \frac{1}{2}\\\\Odp. \ B.[/tex]
[tex]\frac{2^{8}-2^{7}}{16^{2}} =\frac{2^{7}\cdot2-2^{7}}{16^{2}}= \frac{2^{7}(2-1)}{(2^{4})^{2}} = \frac{2^{7}\cdot1}{2^{8}} =\frac{2^{7}}{2^{8}} = 2^{7-8} = 2^{-1} = \frac{1}{2}\\\\Odp. \ B.[/tex]