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oblicz. 3³, 0²⁵⁰, 11², (-½)⁴, (-2¼)², (-0,6)³, (3⅓)⁰, (1,3)²​

Odpowiedź :

Gabrysia66139go

[tex]3^{3} = 3*3*3= 27\\\\[/tex]

zero nieważne do jakiej potęgi zawsze równe jest 0

[tex]11^{2} = 11*11 =121[/tex]

[tex](-\frac{1}{2} )^{4} = \frac{1}{16}[/tex]

[tex]-2\frac{1}{4} =-\frac{9}{4} \\(-\frac{9}{4} )^{2} = \frac{81}{16}[/tex]

[tex]-0,6 = -\frac{6}{10} = -\frac{3}{5} \\(-\frac{3}{5} )^{3} = -\frac{9}{25} * -\frac{3}{5} =\frac{27}{125}[/tex]

wszystko co jest do potęgi zerowej to 1

[tex]1,3 = \frac{13}{10} \\(\frac{13}{10})^{2} = \frac{169}{100}[/tex]

Basetlago

[tex]3^{3} =3\cdot3\cdot3 = 27\\\\0^{250} = 0\\\\11^{2} = 11\cdot11 = 121\\\\(-\frac{1}{2})^{2} = (-\frac{1}{2})\cdot(-\frac{1}{2})\cdot(-\frac{1}{2})\cdot(-\frac{1}{2}) = \frac{1}{16}\\\\(-2\frac{1}{4})^{2} = (-\frac{9}{4})^{2}= (-\frac{9}{4})\cdot(-\frac{9}{4}) = \frac{81}{16} = 5\frac{1}{16}\\\\(-0,6)^{3} = (-0,6)\cdot(-0,6)\cdot(-0,6) = -0,216\\\\(3\frac{1}{3})^{0} = 1\\\\1,3^{2} = 1,3\cdot1,3 = 1,69[/tex]

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