Odpowiedź:
b
[tex]6 {x}^{2} - 5x - 4 < 0 \\ delta = {5}^{2} + 4 \times 4 \times 6 = 25 + 96 = 121 \\ \sqrt{delta} = 11 \\ x = \frac{5 - 11}{12} = - \frac{1}{2} \\ x = \frac{5 + 11}{12} = \frac{4}{3} [/tex]
