Odpowiedź :
[tex]m = 5 \ kg\\E_{p} = 2,4 \ kJ = 2 \ 400 \ J\\g = 10\frac{N}{kg}\\h = ?\\\\E_{p} = mgh \ \ /:mg\\\\h = \frac{E_{p}}{mg}\\\\h = \frac{2400 \ J}{5 \ kg\cdot10\frac{N}{kg}} = \frac{2400 \ N\cdot m}{50 \ N}\\\\h = 48 \ m[/tex]
[tex]m = 5 \ kg\\E_{p} = 2,4 \ kJ = 2 \ 400 \ J\\g = 10\frac{N}{kg}\\h = ?\\\\E_{p} = mgh \ \ /:mg\\\\h = \frac{E_{p}}{mg}\\\\h = \frac{2400 \ J}{5 \ kg\cdot10\frac{N}{kg}} = \frac{2400 \ N\cdot m}{50 \ N}\\\\h = 48 \ m[/tex]