Odpowiedź :
f(x)=log2 x
x∈{1/2,1,2,4,32}
f(1/2)=log2 (1/2)=log2 2^-1=-1·log2 2=-1
f(1)=log2 1=0 , bo 2^0=1
f(2)=log2 2=1
f(4)=log2 4=log2 2²=2log2 2=2·1=2
f(32)=log2 32=log2 2^5=5log2 2=5·1=5
Zwf={-1,0,1,2,5}
f(x)=log2 x
x∈{1/2,1,2,4,32}
f(1/2)=log2 (1/2)=log2 2^-1=-1·log2 2=-1
f(1)=log2 1=0 , bo 2^0=1
f(2)=log2 2=1
f(4)=log2 4=log2 2²=2log2 2=2·1=2
f(32)=log2 32=log2 2^5=5log2 2=5·1=5
Zwf={-1,0,1,2,5}