Witaj :)
Zadanie 1.
[tex]M_{Al_2S_3}=2\cdot M_{Al}+3\cdot M_S=2\cdot 27g/mol+3\cdot 32g/mol =54g/mol+96g/mol =150g/mol[/tex]
- siarczan(VI) żelaza(III) Fe₂(SO₄)₃
[tex]M_{Fe_2(SO_4)_3}=2\cdot M_{Fe}+3\cdot M_S+3\cdot4\cdot M_O= 2\cdot 56g/mol+3\cdot 32g/mol+3\cdot4\cdot 16g/mol = 112g/mol+96g/mol+192g/mol=400g/mol[/tex]
Zadanie 2.
[tex]M_{H_2O}=2\cdot M_H+M_O=2\cdot 1g/mol+16g/mol = 18g/mol\\\\n=\frac{m_s}{M_{H_2O}}=\frac{80g}{18g/mol} =4,44mol[/tex]
[tex]M_{PbI_2}=M_{Pb}+2\cdot M_I= 207g/mol+2\cdot127g/mol=207g/mol+254g/mol=461g/mol\\\\n=\frac{m_s}{M_{PbI_2}}=\frac{121g}{461g/mol}=0,26mol[/tex]
