Odpowiedź:
[1 2/3a + 1 1/2a²b - (0,5bx² + 15abx)] + [a/3- 1/6a²b - ( 1 1/2bx² - 15abx)] =
= [1 2/3a + 1 1/2a²b - 0,5x² - 15abx] + [a/3 - 1/6a²b - 1 1/2bx² + 15abx] =
= 1 2/3a + 1 1/2a²b - 1/2bx² - 15abx + a/3 - 1/6a²b - 1 1/2bx² + 15abx =
= 1 2/3a + 1 1/3a²b + a/3 - 2bx²
( 1 1/2a²b - 1/6a²b = 1 3/6a²b - 1/6a²b = 1 2/6a²b = 1 1/3a²b )
Szczegółowe wyjaśnienie:
