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18. Oblicz:
a) (1 3/4)^6 × (2/7)^6
b) (0,8)^4 : (2 2/3)^4
c) (4 1/2)^3 × (-2)^3
d) (2 1/2)^4 × 0,6^4 :(-15)^4

Z obliczeniami !! :-)
daje najj​


18 Oblicza 1 346 276b 084 2 234c 4 123 23d 2 124 064 154Z Obliczeniami Daje Najj class=

Odpowiedź :

a)

(1 3/4)^6·(2/7)^6=(7/4·2/7)^6=(1/2)^6=1/64

b)

(0,8)^4:(2 2/3)^4=(0,8:2 2/3))^4=(4/5:8/3)^4=(4/5·3/8)^4=(3/10)^4=81/10000

c)

(4 1/2)³·(-2/3)³·(-2)³=(9/2·(-2/3)·(-2))³=6³=216

d)

(2 1/2)^4·(0,6)^4:(-15)^4=(5/2·3/5:(-3/2))^4=(3/2·(-2/3))^4=(-1)^4=1

Odpowiedź:

[tex]a)\ \ (1\frac{3}{4})^6\cdot(\frac{2}{7})^6=(1\frac{3}{4}\cdot\frac{2}{7})^6=(\frac{\not7^1}{\not4_{2}}\cdot\frac{\not2^1}{\not7_{1}})^6=(\frac{1}{2})^6=\frac{1}{64}\\\\\\b)\ \ (0,8)^4:(2\frac{2}{3})^4=(0,8:2\frac{2}{3})^4=(\frac{4}{5}:\frac{8}{3})^4=(\frac{\not4^1}{5}\cdot\frac{3}{\not8_{2}})^4=(\frac{3}{10})^4=\frac{81}{10000}[/tex]

[tex]c)\ \ (4\frac{1}{2})^3\cdot(-\frac{2}{3})^3\cdot(-2)^3=(4\frac{1}{2}\cdot\frac{2}{3}\cdot2)^3=(\frac{\not9^3}{\not2_{1}}\cdot\frac{\not4^2}{\not3_{1}})^3=6^3=216\\\\\\d)\ \ (2\frac{1}{2})^4\cdot0,6^4:(-1,5)^4=(2\frac{1}{2}\cdot0,6:1,5)^4=(\frac{\not5^1}{2}\cdot\frac{3}{\not5_{1}}:\frac{15}{10})^4=(\frac{3}{2}:\frac{3}{2})^4=1^4=1[/tex]