Odpowiedź:
a=[tex]\sqrt{79}[/tex]
[tex]a^{2} +11^{2} =(10\sqrt{2})^{2} \\a^{2} = 200-121\\a^{2} =79\\a=\sqrt{79}[/tex]
m=[tex]\sqrt{65}[/tex]
[tex]\sqrt{17} + (4\sqrt{3})^{2} = m^{2} \\17+48=m^{2} \\65=m^{2} \\\sqrt{65} =m[/tex]
