Odpowiedź :
[tex]dane:\\F_{w} = 50 \ N\\a = 2,5\frac{m}{s^{2}} = 2,5\frac{N}{kg}\\szukane:\\m = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki:\\\\a = \frac{F_{w}}{m} \ \ /\cdot m\\\\a\cdot m = F_{w} \ \ /:a\\\\m = \frac{F_{w}}{a}\\\\m = \frac{50 \ N}{2,5\frac{N}{kg}} = 20 \ kg[/tex]