Odpowiedź:
a) [tex]\frac{2x+3}{5}[/tex] = [tex]\frac{2-x}{3}[/tex] - x | · 15
3(2x+3) = 5(2-x) - 15x
6x+9 = 10-5x-15x
6x+9 =10-20x
6x+20=10-9
26x=1 | : 26
x = [tex]\frac{1}{26}[/tex]
b) [tex]\frac{x+1}{2}[/tex] - [tex]\frac{x-1}{3}[/tex] = [tex]\frac{1}{4}[/tex] | · 12
6(x+1)-4(x-1)=3
6x+6 - 4x +4= 3
2x+10=3
2x=3-10
2x = - 7 |: 2
x = - [tex]\frac{7}{2}[/tex]
lub x= -3,5
c) [tex]\frac{4x+7}{2}[/tex] - [tex]\frac{5x-1}{6}[/tex] = x+5|· 6
3(4x+7) - (5x-1)=6x+30
12x+21-5x+1=6x+30
7x+22=6x+30
7x-6x=30-22
x=8
d) [tex]\frac{x+5}{4}[/tex] - [tex]\frac{2x+1}{8}[/tex] = [tex]\frac{1}{2}[/tex] (2-x)
[tex]\frac{x+5}{4}[/tex] - [tex]\frac{2x+1}{8}[/tex] = 1 - [tex]\frac{1}{2}[/tex]x |· 8
2(x+5) - (2x+1) = 8 - 4x
2x+10-2x-1=8-4x
10-1=8-4x
9=8-4x
4x=8-9
4x=x - 1 : 4
x= - [tex]\frac{1}{4}[/tex]
Szczegółowe wyjaśnienie:
