Odpowiedź :
[tex]1)\\\\ (x-4)(x+4)=(x+1)^2-17 \\\\x^2-16=x^2+2x+1-17\\\\ x^2-x^2-2x=1-17+16\\\\-2x=0\ \ |:(-2)\\\\x=0[/tex]
[tex]2)\\\\ 2x^2+2x+1=(x+5)^2+2(x^2-16)-1\\\\ 2x^2+2x+1= x^2+10x+25 +2 x^2-32-1\\\\ 2x^2+2x+1= 3x^2+10x-8\\\\2x^2-3x^2+2x-10x+1+8=0\\\\-x^2-8x+9=0\\\\a=-1,\ \ b=-8,\ \ c=9[/tex]
[tex]\Delta =b^2-4ac=(-8)^2-4*(-1)*9=64+36=100\\\\\sqrt{\Delta }=\sqrt{100}=100\\\\x_{1}=\frac{-b-\sqrt{\Delta }}{2a}=\frac{8-10}{2*(-1)}=\frac{-2}{-2}=1\\\\x_{2}=\frac{-b+\sqrt{\Delta }}{2a}=\frac{8+10}{2*(-1)}=\frac{18}{-2}= -9[/tex]