Odpowiedź :
Odpowiedź:
A = (- 2 , 4 ) , B = ( 5 , - 6 ) ,
S - środek odcinka IABI = ( xs , ys)
xa = - 2 , xb = 5 , ya = - 6
xs = (xa +xb)/2 = ( - 2 + 5)/2 = 3/2 = 1 1/2
ys = (ya+yb)/2 = ( 4 - 6)/2 = - 2/2 = - 1
S = ( 1 1/2 ; - 1 )
Odpowiedź:
A = (- 2 , 4 ) , B = ( 5 , - 6 ) ,
S - środek odcinka IABI = ( xs , ys)
xa = - 2 , xb = 5 , ya = - 6
xs = (xa +xb)/2 = ( - 2 + 5)/2 = 3/2 = 1 1/2
ys = (ya+yb)/2 = ( 4 - 6)/2 = - 2/2 = - 1
S = ( 1 1/2 ; - 1 )