Odpowiedź :
[tex]y=ax+b\\\\ax+b=y\\\\ax-y=-b\ \ \ |:(-b)\\\\\frac{ax}{-b}-\frac{y}{-b}=1\\\\\frac{ax}{-b}+\frac{y}{b}=1\\\\\frac{a}{-b}x+\frac{y}{b}=1\\\\\frac{x}{\frac{-b}{a}}+\frac{y}{b}=1[/tex]
[tex]y=ax+b\\\\ax+b=y\\\\ax-y=-b\ \ \ |:(-b)\\\\\frac{ax}{-b}-\frac{y}{-b}=1\\\\\frac{ax}{-b}+\frac{y}{b}=1\\\\\frac{a}{-b}x+\frac{y}{b}=1\\\\\frac{x}{\frac{-b}{a}}+\frac{y}{b}=1[/tex]