Odpowiedź :
Zadanie 1
a) siarczan(VI)sodu-woda (1/10)
b) Mg(NO3)2*6H2O
Zadanie 2
2CaSO4*H2O=2*(40u+32u+4*16u)+18u=290 u
18u---x%
290u---100%
x=6,21% H2O
Zadanie 3
a) 2 (CaSO4*2H2O)--->2CaSO4*H2O+3 H2O
b) 2CaSO4*H2O+3 H2O--->2 (CaSO4*2H2O)
Zadanie 1
a) siarczan(VI)sodu-woda (1/10)
b) Mg(NO3)2*6H2O
Zadanie 2
2CaSO4*H2O=2*(40u+32u+4*16u)+18u=290 u
18u---x%
290u---100%
x=6,21% H2O
Zadanie 3
a) 2 (CaSO4*2H2O)--->2CaSO4*H2O+3 H2O
b) 2CaSO4*H2O+3 H2O--->2 (CaSO4*2H2O)