Odpowiedź:
[tex]P = \frac{1}{2} * (2 + \sqrt{2}) * (4 - \sqrt{2})[/tex]
[tex]P = \frac{1}{2} * (8 - 2\sqrt{2} + 4\sqrt{2} - 4)[/tex]
[tex]P = \frac{1}{2} * (4 + 2\sqrt{2})[/tex]
[tex]P = 2 + \sqrt{2}[/tex]
Odp. Pole rombu wynosi [tex]2 + \sqrt{2}[/tex].