Odpowiedź:
[tex]s(t)=\dfrac{1}{2}bt^2+\dfrac{2}{3}ct^3[/tex]
Wyjaśnienie:
[tex]s(t)=\displaystyle\int_0^tv(t)\,dt=\int_0^t(bt+2ct^2)\,dt=\left(\frac{1}{2}bt^2+\frac{2}{3}ct^3+C\right)\biggr\rvert_0^t=\\\\\boxed{\frac{1}{2}bt^2+\dfrac{2}{3}ct^3}[/tex]