Odpowiedź:
C. 6.
Szczegółowe wyjaśnienie:
[tex]c = 5\\b = h = 3\\a = ?\\P = ?\\\\Z \ tw. \ Pitagorasa:\\\\a^{2}+b^{2}=c^{2}\\\\a^{2}+3^{2}=5^{2}\\\\a^{2}+9 = 25\\\\a^{2} = 25-9\\\\a^{2} = 16\\\\a = \sqrt{16}\\\\\underline{a = 4}\\\\\\P = \frac{1}{2}ah} = \frac{1}{2}ab\\\\P = \frac{1}{2}\cdot 4\cdot3\\\\\boxed{P = 6}[/tex]
