Odpowiedź:
-3x²-3x+7=0 /*(-1)
3x²+3x-7=0
Δ=9-4*3*(-7)
Δ=9+84
Δ=93
[tex] \sqrt{Δ} = 93[/tex]
[tex]x_1 = \frac{ - 3 - \sqrt{93} }{6} [/tex]
[tex]x_2 = \frac{ - 3 + \sqrt{93} }{6} [/tex]
[tex]-3x^{2}-3x+7 = 0 \ \ \ |\cdot(-1)\\\\\underline{3x^{2}+3x-7 = 0}\\\\a = 3, \ b = 3, \ c = -7\\\\\Delta = b^{2}-4ac = 3^{2}-4\cdot3\cdot(-7) = 9 + 84 = 93\\\\\sqrt{\Delta} = \sqrt{93}\\\\x_1 = \frac{-b-\sqrt{\Delta}}{2a}=\frac{-3-\sqrt{93}}{2\cdot3} = \frac{-3-\sqrt{93}}{6}\\\\x_2 = \frac{-b+\sqrt{\Delta}}{2\cdot3}=\frac{-3+\sqrt{93}}{6}\\\\\boxed{x \in \{\frac{-3-\sqrt{93}}{6}, \frac{-3+\sqrt{93}}{6}\}}[/tex]
