[tex]d=100m\\\\sin30=\frac{a}d\\\frac12=\frac{a}{100m}\\a=\frac{100m}2=50m\\\\cos30=\frac{b}d\\\frac{\sqrt3}2=\frac{b}{100m}\\b=\frac{100\sqrt3m}2=50\sqrt3m\\\\P=ab \to P=50m*50\sqrt3m=2500\sqrt3m^2\\Ob=2a+2b \to P=2*50m+2*50\sqrt3m=100m+100\sqrt3m=(100+100\sqrt3)m[/tex]
