Odpowiedź:
[tex]y=-x^2-x+6\\\\-x^2-x+6=0\\\\a=-1\ \ ,\ \ b=-1\ \ ,\ \ c=6\\\\\Delta=b^2-4ac\\\\\Delta=(-1)^2-4\cdot(-1)\cdot6=1+24=25\\\\\sqrt{\Delta}=\sqrt{25}=5\\\\x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5}{2\cdot(-1)}=\frac{1-5}{-2}=\frac{-4}{-2}=2\\\\x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5}{2\cdot(-1)}=\frac{1+5}{-2}=\frac{6}{-2}=-3[/tex]
[tex]Zapisujemy\ \ wz\'or\ \ funkcji\ \ w\ \ postaci\ \ iloczynowej\\\\y=a(x-x_{1})(x-x_{2})\\\\y=-1(x-2)(x-(-3))\\\\y=-(x-2)(x+3)[/tex]
