[tex]Dane:\\E = 1\frac{2}{10} \ eV = 1,2 \ eV = 1,2\cdot1,6\cdot10^{-19} \ J = 1,92 \ J\\1 \ eV = 1,6\cdot10^{-19} \ J\\h = 6,63\cdot10^{-34} \ Js\\c = 3\cdot10^{8}\frac{m}{s}\\Szukane:\\\lambda = ?[/tex]
Rozwiązanie
Z definicji fotonu:
[tex]E = \frac{h\cdot c}{\lambda} \ \ \rightarrow \ \ \lambda = \frac{h\cdot c}{E}\\\\\lambda = \frac{6,63\cdot10^{-34} \ Js\cdot3\cdot10^{8}\frac{m}{s}}{1,92\cdot10^{-19} \ J}=10,359\cdot10^{-7} \ m\\\\\boxed{\lambda = 1035,9 \ nm \approx1036 \ nm}[/tex]
