Czy ktoś pomoże mi z zadaniami 13 i 14 ze str 37
Plisss daje najjj 90 p

a) [tex]a - 1\frac{5}{6} = 1\frac{3}{6}[/tex]
[tex]a = 1\frac{3}{6} + 1\frac{5}{6}[/tex]
[tex]a = 3\frac{2}{6} = 3\frac{1}{3}[/tex]
b) [tex]x + 3\frac{3}{4} = 5\frac{2}{4}[/tex]
[tex]x = 5\frac{2}{4} - 3\frac{3}{4}[/tex]
[tex]x = 1\frac{3}{4}[/tex]
c) [tex]4\frac{1}{3} - b = 1\frac{2}{3}[/tex]
[tex]\frac{13}{5} - b = \frac{5}{3}[/tex]
[tex]-b = \frac{5}{3} - \frac{13}{3}[/tex]
[tex]-b = -\frac{8}{3}[/tex]
[tex]b= \frac{8}{3} = 2\frac{2}{3}[/tex]
x - wagon, z którego odpadła kartka
[tex]15\frac{3}{5} + 14\frac{2}{5} + x + 16\frac{4}{5} + 16 = 80[/tex]
[tex]62\frac{4}{5} + x = 80[/tex]
[tex]x = 80 - 62\frac{4}{5}[/tex]
[tex]x = 17\frac{1}{5}[/tex]
Odpowiedź. Na tej kartce było zapisane [tex]17\frac{1}{5}t.[/tex]
Odpowiedź:
[tex]Zad.13\\\\a)\\\\a-1\frac{5}{6}=1\frac{3}{6}\\\\a=1\frac{3}{6}+1\frac{5}{6}\\\\a=2\frac{8}{6}\\\\a=3\frac{2}{6}\\\\Spr.\\\\L=3\frac{2}{6}-1\frac{5}{6}=2\frac{8}{6}-1\frac{5}{6}=1\frac{3}{6}\\\\P=1\frac{3}{6}\\\\L=P[/tex]
[tex]b)\\\\x+3\frac{3}{4}=5\frac{2}{4}\\\\x=5\frac{2}{4}-3\frac{3}{4}\\\\x=4\frac{6}{4}-3\frac{3}{4}\\\\x=1\frac{3}{4}\\\\Spr.\\\\L=1\frac{3}{4}+3\frac{3}{4}=4\frac{6}{4}=5\frac{2}{4}\\\\P=5\frac{2}{4}\\\\L=P[/tex]
[tex]c)\\\\4\frac{1}{3}-b=1\frac{2}{3}\\\\-b=1\frac{2}{3}-4\frac{1}{3}\\\\-b=\frac{5}{3}-\frac{13}{3}\\\\-b=-\frac{8}{3}\\\\-b=-2\frac{2}{3}\ \ /\cdot(-1)\\\\b=2\frac{2}{3}\\\\Spr.\\\\L=4\frac{1}{3}-2\frac{2}{3}=3\frac{4}{3}-2\frac{2}{3}=1\frac{2}{3}\\\\P=1\frac{2}{3}\\\\L=P[/tex]
[tex]Zad.14\\\\Obliczymy\ \ ile\ \ ton\ \ wegla\ \ jest\ \ w\ \ wagonach,kt\'ore\ \ posiadaja\ \ kartki\\\\15\frac{3}{5}+14\frac{2}{5}+16\frac{4}{5}+16=29\frac{5}{5}+16\frac{4}{5}+16=30+32\frac{4}{5}=62\frac{4}{5}\\\\\\80-62\frac{4}{5}=79\frac{5}{5}-62\frac{4}{5}=17\frac{1}{5}[/tex]
Odpowiedź: W wagonie z odklejoną kartką jest 17 1/5 t węgla.