[tex](\sqrt[3]{b}\cdot\sqrt[4]{b})^{\frac{1}{3}} = (b^{\frac{1}{3}}\cdot b^{\frac{1}{4}})^{\frac{1}{3}}=(b^{\frac{1}{3}+\frac{1}{4}})^{\frac{1}{3}} = (b^{\frac{4}{12}+\frac{3}{12}})^{\frac{1}{3}} = (b^{\frac{7}{12}})^{\frac{1}{3}} = b^{\frac{7}{12}\cdot\frac{1}{3}}=b^{\frac{7}{36}}[/tex]
Wykorzystano własności potęg:
[tex]a^{m}\cdot a^{n} = a^{m+n}\\\\(a^{m})^{n} = a^{m\cdot n}[/tex]
