[tex]10x^2-3x-1 > 0\\a=10 \text{ - ramiona skierowane w gore}\\\Delta=(-3)^2-4*10*(-1)=9+40=49\\\sqrt{\Delta}=7\\x_1=\frac{3-7}{20}=\frac{-4}{20}=-\frac15\\x_2=\frac{3+7}{20}=\frac{10}{20}=\frac12\\\\x\in(-\infty; -\frac15)U(\frac12; \infty)[/tex]
