Odpowiedź :
[tex] {a}^{2} = (2 + 10) | \sqrt{} \\ a = \sqrt{2 + 10} \\ a = \sqrt{12} \\ a = \sqrt{4 \times 3} \\ a = 2 \sqrt{3} [/tex]
Przekątna
[tex]d = a \sqrt{2} \\ \\d = 2 \sqrt{3} \times \sqrt{2} = 2 \sqrt{6} [/tex]
[tex] {a}^{2} = (2 + 10) | \sqrt{} \\ a = \sqrt{2 + 10} \\ a = \sqrt{12} \\ a = \sqrt{4 \times 3} \\ a = 2 \sqrt{3} [/tex]
Przekątna
[tex]d = a \sqrt{2} \\ \\d = 2 \sqrt{3} \times \sqrt{2} = 2 \sqrt{6} [/tex]