Odpowiedź:
Szczegółowe wyjaśnienie:
a) f(x) = [tex]x^{2} -4x+1\\[/tex]
a=1
b=-4
c=1
Δ= [tex]b^{2} - 4*ac\\[/tex]
Δ = 16 - 4 = 12
p = [tex]-\frac{b}{2a}[/tex] = 2
q =[tex]-\frac{delta}{4a}[/tex] = -3
f(x) = [tex]a(x - p)^{2} +q[/tex]
f(x) = [tex]a(x - 2)^{2} -3[/tex]
b)f(x) = [tex]x^{2} +2x-3\\[/tex]
a=1
b=2
c=-3
Δ= [tex]b^{2} - 4*ac\\[/tex]
Δ = 4 + 4*3*1 = 16
p = [tex]-\frac{b}{2a}[/tex] = -1
q =[tex]-\frac{delta}{4a}[/tex] = -4
f(x) = [tex]a(x - p)^{2} +q[/tex]
f(x) = [tex]a(x + 1)^{2} -4[/tex]
