4.
[tex]a) \ 7-3\sqrt{7}-2,5+5\sqrt{7} = 7-2,5+5\sqrt{7}-3\sqrt{7} = \boxed{4,5+2\sqrt{7}}\\\\\\b) \ 5(2+3\sqrt{6})-2(4+3\sqrt{6})=5\cdot2 + 5\cdot3\sqrt{6} -2\cdot4-2\cdot3\sqrt{6} = 10+15\sqrt{6}-8-6\sqrt{6} =\\\\= 10-8+15\sqrt{6}-6\sqrt{6} =\boxed{2+9\sqrt{6}}\\\\\\c) \ 4(\sqrt[3]{3}-2)-3(\sqrt[3]{3}-4) =4\cdot\sqrt[3]{3}+4\cdot(-2) -3\cdot\sqrt[3]{3}-3\cdot(-4)= 4\sqrt[3]{3}-8-3\sqrt[3]{3}+12 =\\\\= 12-8+4\sqrt[3]{3}-3\sqrt[3]{3} = \boxed{4+\sqrt[3]{3}}[/tex]
