zad 4 daje najjjj oblicz pole i obwód równoległoboku (;

a)
e = 2,4dm
f = 1,8dm
a = 1,5dm
P = e • f • ½ = 2,4dm * 1,8dm * ½ = 2,16dm²
Obw = 4a = 4 • 1,5dm = 6dm
b)
h = 5,4cm
a = 8,5cm
b = 7,2cm
P = ah = 8,5cm • 5,4cm = 45,9cm²
Obw = 2a + 2b = 2 • 8,5cm + 2 • 7,2cm = 17 + 14,4 = 31,4cm
;)