Zadanie z chemii. Klasa 7. Załącznik
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1.
dane:
M(Mg) = 24g/mol
M(MgS) = 56g/mol
ms(Mg) = 6g
Mg + S → MgS
24g - 56g
6g - x
x = (6g * 56g) / 24g = 14g MgS
2.
dane:
M(Al) = 27g/mol
M(Al₂S₃) = 150g/mol
ms(Al) = 108g
2Al + 3S → Al₂S₃
2*27g - 150g
108g - x
x = (108g*150g)/54g = 300g Al₂S₃