Odpowiedź :
Odpowiedź:
[tex](3x+4)(x-3)+(2x+x{)}^{2} = 3 {x }^{2} - 9x + 4x - 12 + 9 {x}^{2} = 12 {x}^{2} - 5x - 12 \\ \\
2x(3x-5)-5(x^{2}-5x+6) = 6 {x}^{2} - 10x - 5 {x}^{2} + 25x - 30 = {x}^{2} + 15x - 30[/tex]
Odpowiedź:
[tex](3x+4)(x-3)+(2x+x{)}^{2} = 3 {x }^{2} - 9x + 4x - 12 + 9 {x}^{2} = 12 {x}^{2} - 5x - 12 \\ \\
2x(3x-5)-5(x^{2}-5x+6) = 6 {x}^{2} - 10x - 5 {x}^{2} + 25x - 30 = {x}^{2} + 15x - 30[/tex]