Odpowiedź :
m(C15H31COO)3C3H5=51*12u+98*1u+6*16u=806 u
%C=612u*100%/806u
%C=75,93%
%H=98u*100%/806u
%H=12,16%
%O=96u*100%/806u
%O=11,91%
m(C15H31COO)3C3H5=51*12u+98*1u+6*16u=806 u
%C=612u*100%/806u
%C=75,93%
%H=98u*100%/806u
%H=12,16%
%O=96u*100%/806u
%O=11,91%