Pole podstawy
[tex]6 \times \frac{ {6}^{2} \sqrt{3} }{4} = 6 \times \frac{36 \sqrt{3} }{4} = 6 \times 9 \sqrt{3} = 54 \sqrt{3} {cm}^{2} [/tex]
Wysokość ściany bocznej
[tex] {3}^{2} + {x}^{2} = {5}^{2} \\ 9 + {x}^{2} = 25 \\ {x}^{2} = 16 \\ x = \sqrt{16} \\ x = 4cm[/tex]
Pole boczne
[tex]6 \times \frac{6 \times 4}{2} = 6 \times \frac{24}{2} = 6 \times 12 = 72 {cm}^{2} [/tex]
Pole całkowite
[tex](54 \sqrt{3} + 72 {)cm}^{2} [/tex]
