Odpowiedź:
[tex]x = \sqrt{ {7}^{2} } - ( {2 \sqrt{10}) }^{2} = \sqrt{49 - 40} = \sqrt{9} = 3[/tex]
[tex]x = \sqrt{( {2 \sqrt{5}) }^{2} - {2}^{2} } = \sqrt{20 - 4} = \sqrt{16 } = 4[/tex]
[tex]x = \sqrt{ ({5 \sqrt{5} )}^{2} - {11}^{2} } = \sqrt{125 - 121} = \sqrt{4} = 2[/tex]
[tex]x = \sqrt{( {6 \sqrt{2} }^{2} - {6)}^{2} } = \sqrt{72 - 36} = \sqrt{36} = 6[/tex]
