Proszę o jak najszybszą pomoc.

a) [tex]x\sqrt{9} - 2^{2} = x\sqrt{25} + \sqrt{4}[/tex]
[tex]3x - 4 = 5x + 2[/tex]
[tex]-2x = 6[/tex]
[tex]x = -3[/tex]

b)
[tex]\sqrt{4}(x + 4^{0} ) = -\sqrt{16} - x[/tex]
[tex]2(x + 1 ) = -4 - x[/tex]
[tex]2x + 2 = -4 - x[/tex]
[tex]3x = -6[/tex]
[tex]x = -2[/tex]

c)
[tex]\frac{x}{\sqrt{36}} + (\sqrt{7} )^{2} = \frac{x + 3^{0} }{\sqrt{9}} - x[/tex]
[tex]\frac{x}6} + 7 = \frac{x + 1 }3} - x[/tex]
[tex]\frac{1}6}x + 7 = \frac{x + 1 }3} - x[/tex] /*3
[tex]\frac{1}{18}x + 21 = x + 1 - 3x[/tex]
[tex]-2\frac{1}{18}x= 20[/tex]
[tex]-\frac{37}{18}x= 20[/tex] /:[tex]-\frac{37}{18}[/tex]
[tex]x= -(20 * \frac{18}{37})[/tex]
[tex]x= -(9\frac{27}{37} )[/tex]

d)

Karooolinka0go Karooolinka0go · Answer 2

Odpowiedź:

a) x * 3 - 4 + x * 5 + 2 c) (x/6) + 2+ x+(1\3) - x

3x - 4 = 5x + 2 x + 12 = 2x +2 - 6x

3x - 5x = 2 + 4 x + 4x= 2 - 12

-2x = 6 5x = 2 - 12

x = -3 5x = -10

b) 2x + 2 + -4 - x x= -2

3x= -4 - 2 d) 3(x + 1) - (-2+ 2x) = 3 - x

3x = - 6 3x + 3 -(-2 + 2x) = 3 - x

x= -2 3x + 2 - 2x = -x

x + 2 = -x

2x= -2

x = -1

Szczegółowe wyjaśnienie:

mam nadzieje ze pomogłam<3