[tex]\frac{2x-4}{8-4x}=\frac{-x+1}{1}\\\\8-4x\neq 0\\\\-4x\neq -8\ \ |:(-4)\\\\x\neq 2\\\\D=R\setminus\left\{2 \right\}\\\\\\\frac{2x-4}{-2(2x-4)}=\frac{-x+1}{1}\\\\\frac{1}{-2}=\frac{-x+1}{1}\\\\-2(-x+1)=1\\\\2x-2=1\\\\2x=1+2\\\\2x=3\ \ |:2\\\\x=\frac{3}{2}[/tex]
