Odpowiedź:
[tex](\frac{2}{7})^2-\frac{2^2}{7}+\frac{2}{7^2}=\frac{4}{49}-\frac{4}{7}+\frac{2}{49}=\frac{6}{49}-\frac{4}{7}=\frac{6}{49}-\frac{28}{49}=-\frac{22}{49}\\\\10\cdot(-0,1)^4-0,1\cdot10^4=10\cdot0,0001-0,1\cdot10000=0,001-1000=-999,999\\\\3^2\cdot\frac{1}{3}-(-\frac{1}{3})^0\cdot(-3)^2=\not9^3\cdot\frac{1}{\not3_{1}}-1\cdot9=3-9=-6[/tex]
