[tex]13dm = 130cm[/tex]
Pole podstawy
[tex] \frac{ {10}^{2} \sqrt{3} }{4} = \frac{100 \sqrt{3} }{4} = 25 \sqrt{3} {cm}^{2} [/tex]
Wysokość ściany bocznej
[tex] {5}^{2} + {h}^{2} = {130}^{2} \\ 25 + {h}^{2} = 16900 \\ {h}^{2} = 16875 \\ h = \sqrt{16875} \\ h = 75 \sqrt{3} cm[/tex]
Pole ściany bocznej
[tex] \frac{10 \times 75 \sqrt{3} }{2} = 5 \times 75 \sqrt{3} = 375 \sqrt{3} {cm}^{2} [/tex]
Pole całkowite
[tex]25 \sqrt{3} +3 \times 375 \sqrt{3} = 25 \sqrt{3} + 1125 \sqrt{3} = \boxed{ 1150 \sqrt{3} {cm}^{2} }[/tex]
