Odpowiedź:
[tex]2log_{4} 12-\frac{1}{2} log_481 = log_412^{2} -log_481^{\frac{1}{2} } = log_4144-log_49=log_4(\frac{144}{9})=log_416=2\\ \frac{1,68}{2\frac{1}{3} } - 0,56= \frac{\frac{42}{25}}{\frac{7}{3} } - \frac{56}{100} = \frac{42}{25}*\frac{3}{7} - \frac{56}{100} = \frac{126}{175}-\frac{56}{100}= \frac{504}{700}-\frac{392}{700} = \frac{112}{700}=\frac{16}{100}= 0,16[/tex]
Liczę na naj :)