a) 6✓18 = 6 ✓9*2 = 6*3 ✓2 = 18✓2
b) 3/4✓20 = 3/4 ✓4*5 = 3/4 * 2✓5 = 3/2✓5
c) ten sam stopień można włożyć pod jeden pierwiastek
✓35*21 = ✓735 = ✓49 * 15 = 7✓15
d) to samo
2✓8*27 = 2✓216 = 12✓16
Odpowiedź:
[tex]a)\ \ 6\sqrt{18}=6\sqrt{9\cdot2}=6\cdot3\sqrt{2}=18\sqrt{2}\\\\b)\ \ \frac{3}{4}\sqrt{20}=\frac{3}{4}\sqrt{4\cdot5}=\frac{3}{\not4_{2}}\cdot\not2^1\sqrt{5}=\frac{3}{2}\sqrt{5}=1,5\sqrt{5}\\\\c)\ \ \sqrt{35}\cdot\sqrt{21}=\sqrt{35\cdot21}=\sqrt{735}=\sqrt{49\cdot15}=\sqrt{49}\cdot\sqrt{15}=7\sqrt{15}\\\\d)\ \ 2\sqrt{8}\cdot\sqrt{27}=2\sqrt{4\cdot2}\cdot\sqrt{9\cdot3}=2\cdot2\sqrt{2}\cdot3\sqrt{3}=4\sqrt{2}\cdot3\sqrt{3}=12\sqrt{2\cdot3}=12\sqrt{6}[/tex]
